Error 400 python

If you do this: import urllib, urllib2 quoted_ query = urllib. quote( query) host. I had a similar problem, i tried changing params to data or with json. dumps( ) : from json import dumps r = requests. post( url, params= dumps( params), auth= ( v_ username, v_ password), data= payload, headers= v_ headers,. 見たところ双方ともサーバ側のエラーのようですので、 提示なされたコードにはエラー などはないのでそれ見ても原因はわかりませんねーまず、 どこの行の実行でどのエラー が出るのかを確認し、 その命令の実行が本当に正しいのかをチェックし. I think it is because you are not encoding your string before appending it to your url. For example, in python3 you should do the following to ' text_ to_ check' before appending it to your url: text_ to_ check. Looks like you are trying to obtain an OAuth 2. 0 access token using the client_ credientials grant. This is described in RFC6749. I see 2 problems here: You must post your fields as application/ x- www- form- urlencoded instead. A 400 error means that the server cannot understand your request ( e. , malformed syntax). That said, its up to the developers on what status code they want to return and, unfortunately, not everyone strictly follows their.

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    Error python

    request with urllib. org/ ' ) as response: html = response. Based on the comments, your server is actually expecting data as a stringified JSON object. As far as the params are concerned, it' d most probably help if they' re declared as a tuple of tuples ( or a dict of dicts). Try the following. Fix your header: req = urllib. Request( url, headers= { ' User- Agent' : ' Mozilla/ 5. It' s User- Agent, not User Agent. Additionally, I would recommend switching over to the requests module. html_ page = requests.